Question

Find the exact real value of arccos (-√2/2)

Answer 1

-1?

Answer 2

pi divided by four

three pi divided by four

seven pi divided by three

negative pi divided by four

Answer 3

\(\bf cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)\ \quad \\\implies cos(\theta)=-\cfrac{\sqrt{2}}{2}\implies cos^{-1}(cos(\theta))=cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)\\ \quad \\
\theta=cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)\)


check your Unit Circle

Answer 4

3pi/4

Answer 5

:)

Answer 6

Thank you(((: