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The length of a rectangle is three times its width. If the area of the rectangle is 75 yd^2, find its perimeter
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Kinda like the last one, L=3W.... so (3W)x(W)=75 to find W. Then Multiply Your W by 3 to find L.
would it be 4w=75? no right??
WxW is \[W ^{2}\]
whats 3w^2 divided by 75..
\[\frac{ 3W^2 }{ 3 }=\frac{ 75 }{ 3 }\]
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divide both sides by 3, so it is 75/3 = 25 which leaves you with \[W= \sqrt{25}\] so get rid of the exponent. \[W=5\]
w=5?
Yea
so L=15
Yep
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then to find the perimiter do you still multiply L & W?
and get 75
So now do P=2L+2W, to find your perimeter.
thats the area. how do i get perimiter
p=40?
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Yea
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