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g(x)= (x+4)^2 +3 - would I shift to left 4 then shift upwards 3 units?
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yep so your vertex would be at (-4, 3)
why would it be -4?
cause of the domain?
in the equation y= a(x-p)^2 +q, the x value of the vertex is negative. in your equation, the x value is positive (x+4) so we assume that it was x-(-4), making the x value -4.
thank you very much
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