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Mathematics 20 Online
OpenStudy (anonymous):

g(x)= (x+4)^2 +3 - would I shift to left 4 then shift upwards 3 units?

OpenStudy (anonymous):

yep so your vertex would be at (-4, 3)

OpenStudy (anonymous):

why would it be -4?

OpenStudy (anonymous):

cause of the domain?

OpenStudy (anonymous):

in the equation y= a(x-p)^2 +q, the x value of the vertex is negative. in your equation, the x value is positive (x+4) so we assume that it was x-(-4), making the x value -4.

OpenStudy (anonymous):

thank you very much

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