OpenStudy (solomonzelman):

Who ever sucks at Math like me come here!!!

3 years ago
OpenStudy (solomonzelman):

I seen a problem I am going to do it, tell me If I am correct.... OK?

3 years ago
OpenStudy (solomonzelman):

\[\sqrt{2r}=2+\sqrt{r-2}\] \[\sqrt{2r}-\sqrt{r-2}=2\] \[2r-2\sqrt{2r(r-2)}+r-2=4\] not done yet....

3 years ago
OpenStudy (solomonzelman):

I am having comp probs hold on...

3 years ago
OpenStudy (solomonzelman):

\[3r-2\sqrt{2r^2-4}+ r-2=4\] \[2\sqrt{2r^2-4}=3r-6\] am doing good so far?

3 years ago
OpenStudy (solomonzelman):

\[8r^2-16=9r^2-32r+52\] \[-r^2+32r-68=0\] \[r^2-32r+68=0\] is this good so far? \[(r-16)^2=188\] \[r= 16 ± 2\sqrt{47}\] right?

3 years ago
OpenStudy (anonymous):

Look what I found! @LifeIsADangerousGame

3 years ago
OpenStudy (anonymous):

this is one of your yesterday's problems isn't it?

3 years ago
OpenStudy (anonymous):

@SolomonZelman, mistake after squaring both sides look over your work.....

3 years ago
OpenStudy (lifeisadangerousgame):

haha yes, this is my problem from yesterday

3 years ago
OpenStudy (lifeisadangerousgame):

You need to square both sides Solomon

3 years ago
OpenStudy (anonymous):

what did you get as answer there do you remember?

3 years ago
OpenStudy (anonymous):

what I am getting is \[r^2+28r+4=0\]

3 years ago
OpenStudy (anonymous):

can't factor

3 years ago
OpenStudy (anonymous):

\[r^2+28=-4\] \[(r+14)^2=-4+196\] \[r=-14± 32\sqrt{3}\]

3 years ago
OpenStudy (anonymous):

r approximately equal to 41.43 or -69.43

3 years ago
OpenStudy (anonymous):

\[3a - 4 \le 5\]

3 years ago
OpenStudy (anonymous):

@Victoria_Cakes20, do the following: (Step by Step) 1) add 4 to both sides 2) divide both sides by 3 do this carefully and correctly (what's your answer?)

3 years ago
OpenStudy (ranga):

(2r)^1/2 = 2 + (r - 2)^1/2 (2r)^1/2 - 2 = (r - 2)^1/2 Square both sides 2r - 4(2r)^1/2 + 4 = r - 2 Take the radical to the right and everything else to the left 2r + 4 - r + 2 = 4(2r)^1/2 r + 6 = 4(2r)^1/2 Square both sides r^2 + 12r + 36 = 16(2r) = 32r r^2 + 12r + 36 - 32r = 0 r^2 - 20r + 36 = 0 r^2 - 2r - 18r + 36 = 0 r(r - 2) - 18(r - 2) = 0 (r - 18)(r - 2) = 0 r = 18 or r = 2

3 years ago
OpenStudy (anonymous):

Yes, how didn't I figured this out?

3 years ago
OpenStudy (anonymous):

And it works perfectly for each.

3 years ago