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the domain of y=1/x+8-1 is all real number except x=-1. true or false?
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Does the function look like this \[\Large y = \frac{ 1 }{ x + 8} - 1\]? OR
yes
\[\Large y = \frac{ 1 }{ x } + 8 - 1\]?
first one
The denominator cannot go to zero because you cannot divide by 0. So (x + 8) should not go to 0. That means x should not be -8. So the domain is all real numbers except x = -8.
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