Question

compute the integrals
x/√ 1-2x dx

Answer 1

\[I=\int\limits \frac{ xdx }{ \sqrt{1-2x} },put \sqrt{1-2x}=y,1-2x=y ^{2},x=\frac{ 1-y ^{2} }{2 }\]
also -2 dx=2y dy,x dx=-y dy
\[I=\int\limits \frac{ -y dy }{y } =-y+c\]
replace the value of y

Answer 2

dear i think in this solution need U and du not y :(