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Mathematics 20 Online
OpenStudy (anonymous):

dy/dx [sinx+cosy=sinxcosy]

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

@ranga

OpenStudy (ranga):

Take each term: sinx, cosy, sinxcosy and find the derivative. Gather up all your y' and express it as y' = something.

OpenStudy (ranga):

Same procedure we did before.

OpenStudy (anonymous):

i am stuck at cosx-cosxcosy=-sinxsinyy'+sinyy'

OpenStudy (loser66):

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