Addition method

4y+5z=-2 5y-3z=16

Multiplied 1st with 3 and 2nd with 5

12y+15z=-6 and 25y-15z=16

37y= 10

divided by 37

ended up with y=10/37

Am I heading down the right path or?

Question

Addition method

4y+5z=-2     5y-3z=16

Multiplied 1st with 3 and 2nd with 5

12y+15z=-6  and 25y-15z=16

37y= 10

divided by 37

ended up with y=10/37

Am I heading down the right path or?

hero · Answer

Well let me use a different method and see if I come up with the same thing as you.

hero · Answer

5y-3z=16
4y+5z=-2 

Subtract the second equation from the first yields:
y - 8z = 18
y = 8z + 18

Substituting y in the original system:
5(8z + 18) - 3z = 16
40z + 90 - 3z = 16
37z = -74
   z = -74/37
`z = -2`

y = 8(-2) + 18
y = -16 + 18
`y = 2`

anonymous · Answer

Thanks

hero · Answer

yw