Write an equation for a circle with center at (-2,7) and diameter of 14

Question

aakashsudhakar · Answer

(h, k) ---> (-2, 7) 
D = 14
D = 2r

2r = 14
r = 7

(x - h)^2 + (y - k)^2 = r^2

Plug in all values given.

(x + 2)^2 + (y - 7)^2 = 49

anonymous · Answer

(X+2)^2 + (Y-7)^2 = 7^2

As genral equation of circle is (x-h)^2 + (Y-k)^2=r^2
where h cuts on x axis
k cuts on y axis
and r is radius= (diameter/2)

anonymous · Answer

wait so whats the answer 2?

anonymous · Answer

(X+2)^2 + (Y-7)^2 = 7^2

anonymous · Answer

oo alright sorry thanks

anonymous · Answer

or 
(X+2)^2 + (Y-7)^2 = 49

anonymous · Answer

No problem

anonymous · Answer

sorry my thing online said both were wrong
;(

anonymous · Answer

not possible

anonymous · Answer

$$\left( x+2 \right)^{2}+(y-7)^{2}=49$$

aakashsudhakar · Answer

^^ Like I said too, what @reshabhraj just said should be the correct answer.

anonymous · Answer

now it said its right...sorry guys my online class is dumb sometimes
now it accepted it though thank yall