There is no war in Ba Sing Se.
My Function:X^3-6x^2+7x-98=f(x)
well if that is the graph of the function and these are the offered functions to that graph the simplest reason is that when x=0, that is the y intercept and the other functions dont intercept at -98
Well it needs to have a y intercept of -100, which means the constant term at the end must be -100 (or at least close to, idk if it's exactly 100)
But getting a full equation from that graph ALONE seems incredibly difficult with no other information given, and the graph not being very clear.
but this is for an amusement park and if the coaster is being made from the functions they all seem like fun functions to ride.
haha good point
lol let's get to the point xP
ok so I did post the function of that graph though
this is his sis talking btw
Idk what you need to answer exactly. I strongly doubt you need to find the equation of the function, because... it'd be very difficult with algebra 2 skills and only the given graph, i think. These other suggestions are invalid because ... because they will not intersect the y-axis at -100.
Davidjohn and agent0smith have answered the question already. "One has suggested g(x) = x3 – 2x2+ 4x – 8, and the other has suggested h(x) = x3 + 5x2 – 8x – 48" Put x = 0 in g(x) and you get g(0) = -8 Put x = 0 in h(x) and you get h(0) = -48 But the graph shows the function intersects the y-axis at -100. So the g(x) and h(x) does not represent the function shown in the graph. That is all you have to answer for this problem.
^yep, and trying to actually come up with the function would be tedious. You'd have a very hard time finding the coefficients of ax^3 + bx^2 + cx, you only know the constant is -100. Calculus would help since you can find the min and max.
no it's ok i dont think I need to solve it just why it's invalid
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