Walking through the word problem please.

Question

anonymous · Answer

attachment

anonymous · Answer

I think I would start out with this equation. 

3x+4y=800

anonymous · Answer

Well I have solved A) and B) portion of the problem. I need to solve for both X and Y of the problem though to find C)

anonymous · Answer

A) $$\frac{ 800-3x }{ 4 }$$

B) $$\frac{ x(800-3x) }{ 4 }$$

C) States to find the dimensions that maxamize the enclosed area. 

X=

Y=

anonymous · Answer

@wio

anonymous · Answer

So I know how to start it. 

X(800-3x)/4 

Needs to be evaluated. The problem is I am not sure if I am getting the right answer.

$$200x-\frac{ 3x^2 }{ 4 }$$

anonymous · Answer

If I am right I would proceed plugging in the numbers into

$$-\frac{ b }{ 2(a) }$$

The only problem is I am not sure how to plug it in with that fraction hanging there

is a 200, and b 3/4?