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Trigonometry
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verify that each equation is an identity
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tan(\[\theta-45degree\])+(\[\theta+45degree\])
Using the special triangle rule, tan45 is 1. So I got tan(\[[(\tan \theta-1)/1+\tan \theta] + [(\tan \theta+1)/1-\tan \theta]\]
to get lcd cross multiply so that would be: \[](\tan \theta-1)(1+\tan \theta) + (\tan \theta+1)(1-\tan \theta)]/(1-\tan \theta)(1+\tan \theta)\]
where is the equation ? what you posted is an expression...
\[\tan(\theta-45°)+\tan(\theta+45°) = 2\tan2\theta \]
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did u cross multiply correctly ?
no, i guess not...
|dw:1382772529305:dw| t = tan theta
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