Question

can you correct my answers?
The first derivative of -t^2(5t+2)^3 is -2t(5t+2)^3 - 15t^2(5t+2)^2
The first derivative of sin^2(3t^2) is 12t(sin 3t^2)(cos 3t^2)
and The first derivative of -5t^2 cos (2t^3) is -10t (cos 2t^3) + 30t^4 sin 2t^3

Answer 1

frist one is correct

Answer 2

[ sin^2(3t^2)]' = 2sin(3t^2) [(sin(3t^2)]'
= 2sin(3t^2) cos(3t^2) [3t^2]'
= 2sin(3t^2) cos(3t^2) 6t

second one is also correct

Answer 3

how about the last one?

Answer 4

correct, too

Answer 5

many thanks @Loser66 :D

Answer 6

thanks a lot too @ganeshie8 :)

Answer 7

ok