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find the domain of the function....
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\[f(x)=3\sqrt{x+1}-1\]
hint : the thing inside radical cannot be negative
otherwordy "x" must not take any values that makes the inside of the radical a negative value
we have a square root here and the domain for it \[\sqrt{x+1} \to x+1\ge0\] \[x \ge -1\]|dw:1382816022018:dw|\
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