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OpenStudy (christos):
4^2 - 4sin^2(x) = 4cos^2 true or false?
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OpenStudy (anonymous):
sin^2+cos^2=1 if i remember correctly
OpenStudy (christos):
yep
OpenStudy (anonymous):
so all you have to do is test by moving the equations over.
OpenStudy (aakashsudhakar):
4^2 - 4sin^2(x) = 4cos^2(x) 4(2 - sin^2(x)) = 4(cos^2(x)) 2 - sin^2(x) = cos^2(x) sin^2(x) + cos^2(x) = 2 ^^ This is not true, therefore the equation you have is false.
OpenStudy (christos):
4 - 4sin^2(x) = 4cos^2 How about this ? True or false ?
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OpenStudy (aakashsudhakar):
^^ That is true, because dividing the 4 from everything gets you... \[1 - sin^2(x) = cos^2(x)\] Which simplifies to... \[sin^2(x) + cos^2(x) = 1\] ^^ This is correct, therefore the equation you have is true.
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