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x ^{sqrt{logx}}=10^{8}
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\[x ^{\sqrt{\log_{10}x }}=10^8\]
Is that the problem?
Yes
Can you lead me through the problem?
Well, by inspection, we can figure out that x is 10^4. Can you see that?
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Yes, I understand that but I do not know what to do after?
\[\sqrt{\log_{10}x }\log_{10}x=8 \]
So log10 x = 8?
Then if we square both sides we have: \[\log_{10}x(\log_{10}x)^2=64 \]
\[(\log_{10}x )^3=64\]
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Now take the third root of both sides:
\[\log_{10}x=4 \]
Now put it into its exponential form
Thank you so much!
yw
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