Question

How to solve this?
lim
x→pi/2
(cos x/ 1- 4x^2/pi^2)

Answer 1

The question is actually like this:

Answer 2

Use L-Hospital maybe?
-\[\Large \frac{-\sin x} {\frac{8x}{\pi^2}}=\lim_{x \rightarrow \frac{\pi}{2}} \frac{-\pi ^2 \sin x}{8x}\]
put pi/2 now

Answer 3

The answer is -1/2. I just need to see the steps or method on solving this

Answer 4

do u know l hospital?

Answer 5

yeah why