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How do I solve 20cos squared x+cos x-1=0 [0,pi]
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can you solve quadratics ? this is quadratic in cos x ....
really?
a=20,b=1,c=-1?
yes! cos x = -b+//sqrt b^2-4ac /2a.... i think you know the formula...
I got -1/4 and 1/5(is that the end of the problem)?
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correct! so, x = cos inverse of -1/4 x=cos inverse of 1/5
do you have choices/options?
nope
it is open-ended
so would the answers be cos inverse=-1/4,1/5?
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yeah
that's it?
like this: x = cos inverse of -1/4 x=cos inverse of 1/5
ty so much
welcome :)
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