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x^3-216
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\((a^3-b^3) = (a-b)(a^2+ab+b^2)\) here a= x b=6
for some reason my answers aren't right, I came up with (x-9)(x^2+8x+9)
you took b= 9 ?
but the cube root of 216 is 72...I'm not understanding where to put the 72 lol
cube root of 216 = 6
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oh..
\(216 =6*6*6\)
soooo.... (x-6)(x^2+6x+72) ????
b^2= 6*6 =36
not 72
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okay so in place of 72 i should put 36
(x-6)(x^2+6x+36) ?
you got it :)
thanks :)
welcome ^_^
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