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Mathematics 9 Online
OpenStudy (anonymous):

and this is precalculus question i cannot join it idk why ,was absent was 3 days , so we do this f(x)=x^2-3 quesion is graph each function with is parent function on the same graph pls explain had operation

OpenStudy (happinessbreaksbones):

@hartnn @Hero @ganeshie8 @robtobey @timo86m @KingGeorge @jdoe0001 @primeralph @e.mccormick @nincompoop @Preetha @electrokid @inkyvoyd @Euler271 @divagirl421 @shamil98 hopefully one of these people can help you. because I'm brain dead.

OpenStudy (anonymous):

but how can i reach them im new

OpenStudy (happinessbreaksbones):

I linked them so that they would see this question. if no one comes them click on one of the names I linked and message them directly. :)

OpenStudy (primeralph):

@happinessbreaksbones Never ask anyone to do that again. Messaging isn't meant for questions.

OpenStudy (anonymous):

its serious and im new to this

OpenStudy (primeralph):

Post a new question about seeking help with graphing.

OpenStudy (happinessbreaksbones):

@primeralph I don't agree with that statement, but my apologies. thanks for helping this person.

OpenStudy (anonymous):

do you know what the graph of x^2 looks like?

OpenStudy (primeralph):

@happinessbreaksbones The person sent me a message of the question, as you advised. Not the way to go.

OpenStudy (happinessbreaksbones):

@primeralph and you helped the person.. if the person is still sending you messages and bothering you, then my apologies. If not, then I don't see the problem here.

OpenStudy (primeralph):

@happinessbreaksbones I helped the person because I was tagged, not because I got a message. There is no justification for giving such advise. It is up to you to decide whether or not to accept that it wasn't right, but until you do, don't ask people to send me messages.

OpenStudy (primeralph):

@happinessbreaksbones I don't understand why you are trying to prove a point either. And I did not read your essay; too long. Good luck.

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