Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

how do I solve 3 sec squared x=sec x?

OpenStudy (jdoe0001):

\(\bf 3sec^2(x)=sec(x)\quad ?\)

OpenStudy (anonymous):

\[ \begin{align} 3\sec^2x &= \sec x\\ 3\sec^2x-\sec x&=0\\ \sec x(3\sec x-1)&=0\\ \sec x&=0& 3\sec x-1&=0 \end{align} \]

OpenStudy (anonymous):

you serious?

OpenStudy (anonymous):

YOU CAN STILL APPLY ALGEBRAIC CONCEPTS?

OpenStudy (jdoe0001):

hmmm....no

OpenStudy (jdoe0001):

\(\bf 3sec(x)=1\implies sec(x)=\cfrac{1}{3}\implies \cfrac{1}{cos(x)}=\cfrac{1}{3}\implies 3 = cos(x)\)

OpenStudy (jdoe0001):

but cosine cannot be greater than 1

OpenStudy (anonymous):

right

OpenStudy (anonymous):

so

OpenStudy (anonymous):

sec x can only equal 0 then?

OpenStudy (jdoe0001):

so EQUATION is false

OpenStudy (anonymous):

but sec x=0?

OpenStudy (anonymous):

both factors must be satisfied to get the given equation

OpenStudy (anonymous):

one problem, is that ok?

OpenStudy (anonymous):

one more problem, ok?

OpenStudy (jdoe0001):

alright

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!