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Physics 7 Online
OpenStudy (anonymous):

A force of 800N stretches a certain spring a distance of 0.100m .What is its potential energy when it is compressed a distance of 7.00cm ?

OpenStudy (anonymous):

Well all you have to do is add or multiply.

OpenStudy (anonymous):

I expect that this spring obeys Hooke's law: Fs =-kx. So you can use the first values to find the spring constant k. Then use the expression for spring energy Es = 1/2 k (x^2)

OpenStudy (anonymous):

Thanks simplephysics. Ur the best!!!

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