Question

Help me with this log .

log(5-2x) = Log (3x+1)

Answer 1

Since we have outsides are the same, just set the insides equal and solve for x.

Answer 2

So you did this:
5-2x=3x+1?

Answer 3

yes

Answer 4

Did you have a problem solving that equation?

Answer 5

do i subtract the 1 from the 5

Answer 6

That's a start.

Answer 7

So you are saying to do this 4-2x=3x right?

Answer 8

yes

Answer 9

Now how do you get your x's together?

Answer 10

i have no idea

Answer 11

Well you want to get your x's together on one side and your non x's together on the side.
you have 4-2x on the left and 3x on the right
how do we get the 2x on the other side.
Well you have minus 2x on the left, to undo subtraction you add.

Answer 12

so do i add it to 3x ??

Answer 13

I was thinking more adding 2x on both sides.

Answer 14

adding 3x wouldn't help but it isn't wrong if you do it to both sides but it would just lead to no where

Answer 15

so how would that look?

Answer 16

Take our equation from like a few minutes ago and add 2x on both sides and you show me what you think it looks like.

Answer 17

2x(4-2x) =3x+2x????

Answer 18

put an addition symbol between 2x and (4-2x) since we added 2x on both sides.
2x+(4-2x)+3x+2x

Answer 19

Now combine like terms on both sides.

Answer 20

2x+(4-2x)+5x ??

Answer 21

darn it 2x+(4-2x)=3x+2x I made a type-o

Answer 22

combine like terms

Answer 23

2x+4-2x=?

Answer 24

then the other side is 3x+2x=?

Answer 25

4+1x??

5x

Answer 26

no on the first but yes on second

Answer 27

2x+4-2x=4 since 2x-2x=0

Answer 28

So we have 2x+(4-2x)=3x+2x
can be written as 4 =5x

Answer 29

Now to get x by itself we divide both sides by?

Answer 30

4?