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Mathematics 11 Online
OpenStudy (anonymous):

nothing

OpenStudy (anonymous):

I'm not really sure, but I believe you could complete the square: x^2-6x+9=-1 (x-3)^2=-1 x-3=I x=3+i

OpenStudy (anonymous):

x-3=i *

OpenStudy (anonymous):

or you could use the quadratic formula for a equation of form \[ax^2+bx+c=0\]\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

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