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f(x)= 2/x-5 and g(x)= 2/x +5
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whats the question here?
what's the question?
how do I solve for (fog)
( f o g ) means you substitute the equation of g(x) into f(x) f(g(x)) = 2/(2/x+5) -5
then simplify.
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well I'm stuck at that point
\[f(g(x)) = 2 \times \frac{ x+5 }{ 2 } - 5\]
do i multiply x/2 for the top and bottom ???
f(g(x)) = x
when dividng fractions you multiply the recipocral
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