Which equation defines the graph of y = x^2 after it is shifted vertically 3 units up and horizontally 2 units right?

y = (x + 2)^2 + 3
y = (x – 3)^2 + 2
y = (x – 2)^2 + 3
y = (x + 3)^2 + 2

Question

Which equation defines the graph of y = x^2 after it is shifted vertically 3 units up and horizontally 2 units right?  

y = (x + 2)^2 + 3
y = (x – 3)^2 + 2
y = (x – 2)^2 + 3
y = (x + 3)^2 + 2

anonymous · Answer

y=(x-2)+3

anonymous · Answer

That's not an answer choice :/

anonymous · Answer

Why did you post a question, leave , and come back 20 minutes later just expecting someone to have answered it for you? That's not the way this website works. You should interact with people to learn how to solve these on your own.

anonymous · Answer

My computer crashed e.e

anonymous · Answer

I know this question has something to do with this formula y = a(x-h)^2+k but my textbook doesn't really explain how to use this formula

anonymous · Answer

2 units to the right $(x-2)^2$
then 3 units up $(x-2)^2+3$