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Mathematics 19 Online
OpenStudy (anonymous):

Find the indicated limit, if it exists.

OpenStudy (anonymous):

OpenStudy (anonymous):

I chose the limit does not exist as my answer.

OpenStudy (anonymous):

It looks like it exists to me. Make sure that when you plug in 0 for one that is less than 0 and greater than 0 that you get the same answer. The one in the middle doesn't matter for the limit.

OpenStudy (anonymous):

okay I got 7.

OpenStudy (anonymous):

nicee!

OpenStudy (anonymous):

Thank You !

OpenStudy (anonymous):

Would you mind aiding me with one more problem?

OpenStudy (anonymous):

just to go back to what i was taking about why the middle number doesnt matter. look at this picture.|dw:1382926691039:dw| even though the dot in the middle is different then both sides. the limit is what both sides are getting to.

OpenStudy (anonymous):

Yes I can Help.

OpenStudy (anonymous):

Thank you for both the explanation and the drawing.

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

Use the given graph to determine the limit, if it exists.

OpenStudy (anonymous):

OpenStudy (anonymous):

theres only 2 question for this one right?

OpenStudy (anonymous):

x-> 2- means that you only have to test the left side or when n < 2 x-> 2+ means that you only have to test the left side or when n > 2 usually you have to test both sides like the first one if they don't specify a side like in the first one you asked me to help you with. So what is the limit from each side?

OpenStudy (anonymous):

It's together, but it would only let me upload separately.

OpenStudy (anonymous):

its ok i think i explained the right thing

OpenStudy (anonymous):

-2; 6?

OpenStudy (anonymous):

@AlexBabich

OpenStudy (anonymous):

@AlexBabich

OpenStudy (anonymous):

you have the write answers. just be specific about which answer is for which. I think you got it. NIce work.

OpenStudy (anonymous):

Okay, it's for the problem I just posted, with the 2. Thank you !

OpenStudy (anonymous):

i just mean that the -2 is the answer to the second part of the problem and the 6 is the answer to the first part but its all good im sure you got it.

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