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How do I solve this system of linear equation using the substitution method? 15x-y=14 3x-4y=18
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first equation... bring y to the right and 14 to the left.. its 15x-14=y
now put the value of y in the second equation
Right, which would lead me to 3x-4(15x-14)=18 3x-60x+56=18 57x=-38
yes....
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-57x=-38 x=2/3 subbing into (2): 3(2/3)+4y=18 2+4y=18 y=16/4=4 solution: (2/3, 4)
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