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Mathematics 18 Online
OpenStudy (anonymous):

Ffacot k2 + 13k +30

OpenStudy (hesan):

(k+3)(k+10)=0

OpenStudy (anonymous):

Did you mean Factor?

OpenStudy (hesan):

k=-3 k=-10

OpenStudy (anonymous):

Find factors of 30 which sum upto 13 (Here you should multiply the coefficient of the constant and the coefficient of the first term , i.e 30 x 1 = 30. Find the factors of the answer you get there i.e 30, which sum upto the coefficient of the middle term i.e 13) The factors are +10 and +3 so K^2 + (+10k) + (+3k) +30 (Here 10k + 3k sums upto 13k , which is the middle term) Take the common factor out , k(k + 10) + 3(k + 10) = 0 so , k+10 = 0 and k+3 = 0 ie. k = -10 and k = -3 are the factors

OpenStudy (hesan):

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