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The line that passes through (1, 5) and (-2, 3)
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first we have to find the slope and then have to use the points to find the y=mx + b equation.
m (slope) = y2 - y1 / x2 - x1 so that is (3-5)/(-2-1) = -2/-3 = 2/3
so now we have to use on of the points ( we will use 1,5) to write the equation in point slope form: y - y1 = m ( x-x1)
that is y - 5 = (2/3)(x-1) and then put the problem in y=mx + b form and you have the equation for your line.
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