Question

factor 5r^2+23r+26

Answer 1

5r^2 + 23r + 26 (multiply 5 and 26, which is 130; find two integers that multiply to equal 130, but add to equal 23, which are 10 and 13)
5r^2 + 10r + 13r + 26 (group into pairs)
(5r^2 + 10r) + (13r + 26) (factor each group)
5r(r + 2) + 13(r + 2) (put into factor form)
(5r + 13)(r + 2) <===ANSWER

Answer 2

hope it helps