Question

Differentiate the function.

y=4^x + 4/x

I guess you start by factoring out the 4 in each term?

y= 4(1^x + 1/x)
y = 4(1^x +(-1/x^-2))

Hmm... I know that's wrong...

Answer 1

I got it!

d/dx f(x) = d/dx (4^x + 4/x)
= d/dx (4^x) + 4 * d/dx (1/x)
= 4 + (-d/dx (x) / x^2) + ln 4 * 4^x
= ln (4) * 4^x - (4*1/x^2)
= ln (4) * 4^x - (4/x^2)