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Write the expression 125m^6 - 8n^3 in factored form.
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\[(5m^2-2n)(25m^4+10m^2n+4n^2)\]
could you explain how you got that please?
Use this formula \[a^3-b^3=(a-b)(a^2+ab+b^2)\]
(125m^6)^3-(-8n^3)^3= .. like that?
Well Since both terms are perfect cubes, find the values for a and b.\[a^3=125m^6 so, a=5m^2\] and \[b^3=8n^3, so, b=2n\]
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and plug those into the equation instead?
The binomial can be factored using the difference of cubes formula, because both terms are perfect cubes. So you would do \[(5m^2-2n)(25m^4+10m^2n+4n^2)\]
okaay
thanks
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