Question

If a projectile is launched with an initial velocity of 209 meters per second (209 m/s) from
a rooftop 27 meters (27 m) above ground level, at what time will the projectile return to ground
level? Round your answer to the nearest tenth of a second. Note: The acceleration due to gravity
near the earth's surface is 9.8 meters per second per second (9:8m=s2).
having trouble figuring out answer have the formula right
y=y0+vot-1/2gt^2

Answer 1

y=27+209t-4.9t^2

Answer 2

the formula should be 27 = 0 + 209 t + 4.9t^2

Answer 3

I think so, and solve for t.