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a stone is thrown vertically upward with a speed of 12.0m/s from the edge of a cliff 70.0m high. How long does it take to reach the bottom of the cliff?
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\[x_f = x_i + v_it + \frac{1}{2}at^2\] Solve for t with xf = -70m, xi = 0m, vi = 12 m/s, a = -9.8 m/s^2
physicsguru i believe you should be using 'y's instead of x's lol
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