Question

a stone is thrown vertically upward with a speed of 12.0m/s from the edge of a cliff 70.0m high. How long does it take to reach the bottom of the cliff?

Answer 1

\[x_f = x_i + v_it + \frac{1}{2}at^2\] Solve for t with xf = -70m, xi = 0m, vi = 12 m/s, a = -9.8 m/s^2

Answer 2

physicsguru i believe you should be using 'y's instead of x's lol