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how to calculate a yearly interest into a monthly interest (compound)
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\[Amount= P(1+\frac{(R/12) }{ 100 })^{12n}\]
@chuy99 is that r divided by 12?
yes
can i please have some help putting it into the formula?
@chuy99 so if i had 6% would i divide 6 by 12?
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or 0.06?
.06
\[10000(1+\frac{0.06 \div 12 }{ 100 })\]
6% annual becomes 6/12 % monthly = 6/1200
which is same as, 0.06/12
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