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So I gotta a big anxiety on this , THE RULE IS: any number raised to 0 is = 1. How about 0 raised to 0 ? 0^0
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0^0 is undefined
I think..
I see, thank you :)
nope, it's actually 1...
ohh no, anxiety :/
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...let's put it in wolframalpha and see what it says...
by definition its indeterminate but the limit of x^x as x->0 is 1
So i guess I'll go with undefined then.
yep, undefined. wolframalpha says.
thanks again :)
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