use elimination to solve the system. 3x+5y=6 2x-4y=4
3x + 5y = 6 --> (2) 2x - 4y = 4 --> (-3) ---------------- 6x + 10y = 12 (result of multiplying by 2) -6x + 12y = -12 (result of multiplying by -3) ----------------add 22y = 0 y = 0 now sub 0 in for y in either of the above equations 3x + 5y = 6 3x + 5(0) = 6 3x = 6 x = 2 check.... 2x - 4y = 4 2(2) - 4(0) = 4 4 = 4 (correct) x = 2 and y = 0 or (2,0) any questions ?
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