Anyone knows much about logarithmic equations? I need help. log base 3(x^2-4x-18)=3. Or if you can only help me to factor out the quadratic part would help too.

Question

anonymous · Answer

Write your log equation in exponential form.

So you get 3^3 = x^2 - 4x - 18
Or, 27 = x^2 -4x - 18.

Set the quadratic equal to zero, and solve for x. Make sure you check that the value(s) of x work in the ORIGINAL equation.

isaiah.feynman · Answer

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