Suppose x=9 tan (theta) and the angle (theta) is in the first quadrant. Write algebraic expressions for sin (theta) and cos (theta) and in terms of x .
Hint: since x = 9 tan (theta), then divide both sides, you get x/9 = tan (theta). Now let's draw a triangle and show that.
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So you want, sin (theta) = opposite leg/hypotenuse and cos theta = adjacent leg/hypotenuse Can you figure out the hypotenuse???
oops! its sin= x/9
I dont understand that equation you wrote.
You mean, sin(theta) = x/9?
suppose sin (theta)= x/9 and angle theta is in the first quadrant. Write an algebraic expression for cos( theta) and tan( theta) in terms of x
Draw a triangle...watch!
sorry that was the question
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cos (theta) = ?/9 tan (theta) = x/? You figure out ? using Pythagorean Theorem.
so I figure out what is the adjacent side
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