PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Write the equation for the vertical line that contains point E(10, -3).
All vertica lines have the equation x = b, where b is any real number. Your x-value is 10, so the equation would be x = 10.
oMGOSH thanks so much xx
can you help with just one more?
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whats the question?
Write the equation for the vertical line that contains point E(10, -3). Write it in Slope Intercept Form
The vertical line, as we just said, is x = 10. It cannot be written in slope-intercept form. Slope-intercept form is y = mx + b. We cannot write x = 10 in that form.
im sorry wrong question one sec i worte the wrong ?
ok
What is an equation for the line that passes through points (-1, -4) and (1, 4)
in slope intercept form
First you need to find the slope of the line passing through those two points. Slope = difference in y-values/difference in x-values
slope = (4 - (-4))/(1 - (-1)) = 8/2 = 4 So we know the slope, m, is 4.
We want to write it in slope-intercept form, that is in the form y = mx + b. m = slope b = y-intercept., All what we need to do, is to find, b, the y-intercept. That's pretty easy. We have y = 4x + b (becuase the slope is 4).
Now, take any of the two points you gave, say (1,-1), and plug it into the equation y = 4x + b, and we will solve for b. So, -1 = 4(1) + b - 1 = 4 + b b = - 5 So the equation will be y = 4x - 5.
Thanks so much you don't know how much you have helped. You are better than my math teacher lol . Thank you!
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