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What are the zeros of the polynomial function: f(x) = x3 + x2 – 6x ? 0, –3, 2 0, 3, –2 0, –3, –2 0, 3, 2
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first factor "x" x(x^2+x-6) and go on
x3+x2−6x
(x)(x+3)(x-2) solve for x . x=0 , x=-3, x=2
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