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find the domain of the function...
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\[f(x)=\sqrt{3x-2}\]
You can ONLY take the square root of a number that is zero or graeter than zero. so you want 3x - 2 to be = to 0 or graeter than o. so solve the inequality 3x - 2 > or = to 0.
what do you get?
@meg_72 you got this?
no lol i wasnt at school for this lesson and i dont have all the notes
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start with \[3x-2\geq 0\] add \(2\) and get \[3x\geq 2\] divide by \(3\) and get the domain as \[x\geq \frac{2}{3}\]
oh okay!! Thank you!!!
yw
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