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the area of a rectangle is 65 ft ^2, and the length of the rectangle is 3 ft less than twice the width. find the dimensions of the rectangle
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\[ A=lw=(w-3)w \]
Also \(A=65\)
So the equation is\[ 65=(w-3)w \]
@ashleynicolee Can you solve for \(w\)?
i got -6.70
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@wio
There are two solutions for \(w\), but we know that \(w\) must be positive.
9.70
Correct.
Try to come up with the equation on your own next time
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