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Find the area of the triangle with a = 11.8, b = 12.6, c = 14.8. Round to the nearest tenth.
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sounds like a herons rule ....
I was thinking about that myself.
i hate herons rule :)
Nah, it is simple enough.
It is a two step process, 1) We need to calculate "s", which is half of the triangle perimeter. \(\displaystyle s=\frac{a+b+c}{2}\) 2) We can then calculate the area using a neat little formula! \(A=\sqrt{s(s-a)(s-b)(s-c)}\)
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|dw:1383148570470:dw|
lol, i swear i can find the hardest way to do the simplest tasks :)
It is a gift and a curse :P
okay, I'm working it out now. Thanks guys
i developed a right triangle with the given ab, and scaled it to the given c is all
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n = 14.8/sqrt(298) area = 12.6n * 11.8/2
I got 71.7
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