quick medal! help please ! check out the attachment in the comment box for the question. Is the answer 9, 6 & 8?
well... .what did you get for the value of "x"?
replaced the x with the number(s)
did you solve \(\bf x^2 \le 64 \quad ?\)
that will give you what "x" is
idk the steps in order to solve for it @jdoe0001
\(\bf x^2\le 64\qquad \textit{taking square root to both sides}\\ \quad \\ \sqrt{x^2}=\sqrt{64}\implies x = \pm \sqrt{64} \) what's the square root of 64?
lemme remove the = sign \(\bf x^2\le 64\qquad \textit{taking square root to both sides}\\ \quad \\ \sqrt{x^2}\le\sqrt{64}\implies x \le \pm \sqrt{64}\)
anyhow, still though, what's the square root of 64?
8!
\(\large \bf \sqrt{x^2}\le\sqrt{64}\implies x \le \pm \sqrt{64}\implies x \le \pm 8 \)
so that's what "x" is... now check which numbers are LESS THAN OR EQUALS to \(\bf \pm 8\)
o i plug in 8x^2 √64?
well... solving the inequality will just give you what values "x" would be.... so now we know that \(\bf x \le \pm 8\) so, from the list you're meant to check which numbers meet that
let's try ..say 9, is 9 less than or equals to 8? no, so no that one 66... is 66 less than or equals to 8? no... so no that one either
64 equals to 8
64= 8? they look very different
does 6 equal to 8? no right?
so... say.. if we both go to the mall and you buy a $64 dress.. can I buy the same dress with $8? well
if 64 = 8.. I guess I could
so far its 64 & 8?
well.. think about it... is 64 less than or equals to 8?
or is it more than 8 ?
im thinking 8x8=64! lol but its more than 8
... well.. \(\bf 8^2 = 64\qquad 8\ne 64\) so you're right... 64 is more than 8, so it's not that one either
what about 6? is 6 less than or equals to 8?
less than 6!
wel... less than 8, yes, so that one is one what about 8, is 8 less than or equals to 8?
8 equals!
yeap
so overall the answers is 6 & 8! :)
9 is more than 8.... so no dice 66 is more than 8, no dice 64 is more than 8, no dice 6 is less than 8, so ok 8 is equals to 8, so ok too
thanks so much for being patient with me
yw
hey @jdoe0001 sorry to bother you again but isnt the answer for this 9 & 100? the square root of a 100 is 10 9 is less than 10!
\(\large\bf x^2 < 100\implies x<10\) 9 is less than 100 is not less than 10, is actually much more
what I'm doing wrong?
well.. x < 10 means, "x" is LESS, not equals or greater, just LESS than 10
6&9 is less than!
yeap :)
thank youuu :)
yw
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