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Mathematics 6 Online
OpenStudy (anonymous):

fully factor? a^3+a^2+a+1

OpenStudy (anonymous):

(a+1)(a^2+1)

Directrix (directrix):

Factor by grouping: a^3+a^2+a+1 = a² *( a + 1) + 1*(a + 1) = Factor out the common factor of (a+1) (a+1)*(a²+1) --> @waterpologoalie Will (a²+1) factor?

OpenStudy (anonymous):

no?

Directrix (directrix):

@rrakes Code of conduct: OpenStudy values the Learning process - not the ‘Give you an answer’ process Don’t post only answers - guide the asker to a solution http://openstudy.com/code-of-conduct

Directrix (directrix):

@waterpologoalie >>no? I agree. It will not factor again over the set of Reals.

OpenStudy (anonymous):

thanks! that's the answer i got, just wanted to check it was right!

Directrix (directrix):

You're welcome.

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