Question

A light platform is suspended from the ceiling by a spring. A student with a mass of 58 kg climbs onto the platform. When it stops bouncing and reaches its new equilibrium position (x=0), the student notices that the spring has stretched 0.82 m. The student's friend pulls the platform down 0.32 m further and then releases it at t=0.

What is the amplitude of the motion of the student on the platform?

What is the maximum speed of the student?

Answer 1

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Answer 2

@CrazyCountryGirl I don't believe that will help me

Answer 3

ok just search it cause idk

Answer 4

Ok so first we know that the system gets balanced at first. so
mg = kx and we know value of x and m so we get the value of k for the spring.
now we must note one thing.How does the spring stretch.