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simple integration : int e^(z/y) dz somebody check my answer please
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hi
where is your answer ?
-e^(z/y) -----> this is my answer
+c at the end
y is like a constant
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i set this as e^(z*y^(-1))
hmm ok then is it just e^(x/y) ?
|dw:1383095162949:dw|
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