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OpenStudy (anonymous):
if A and B are mutually exclusive and b>0 , show: P(A|A ∪ B) = P(A) /P(A) + P(B) .
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OpenStudy (blockcolder):
\[P(A|A\cup B)=\frac{P(A\cap(A\cup B))}{P(A\cup B)}\]
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